0=-4.9x^2+24.5x+4.9

Solution for 0=-4.9x^2+24.5x+4.9 equation:

0=-4.9x^2+24.5x+4.9

We move all terms to the left:

0-(-4.9x^2+24.5x+4.9)=0

We add all the numbers together, and all the variables

-(-4.9x^2+24.5x+4.9)=0

We get rid of parentheses

4.9x^2-24.5x-4.9=0

a = 4.9; b = -24.5; c = -4.9;
Δ = b2-4ac
Δ = -24.52-4·4.9·(-4.9)
Δ = 696.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24.5)-\sqrt{696.29}}{2*4.9}=\frac{24.5-\sqrt{696.29}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24.5)+\sqrt{696.29}}{2*4.9}=\frac{24.5+\sqrt{696.29}}{9.8}
$